One Way We Can Count $NQ Is as a Correction

I’m not particularly eager to dive in long in the middle of a selloff I just predicted, but I am trying to make sense of the structure on $NQ. One way to do so is as a pair of triangles joined where the first was the B wave of minor (green) A, and the second was itself the whole of minor (green) B. It would look like this:


Following that, we would expect a pretty impulsive minor (green) C which should subdivide as a 5-wave impulse. And so we would try to count it roughly like this:


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